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CUET · MATHS · PYQ PAPER 2025

The absolute maximum value of the function \(f(x)=4 x-\frac{1}{2} x^2\) in the interval \(\left[-2, \frac{9}{2}\right]\) is

  1. A 10
  2. B 9
  3. C 8
  4. D 6
Verified Solution

Answer & Solution

Correct Answer

(C) 8

Step-by-step Solution

Detailed explanation

\(f'(x) = 4 - x\) \(4 - x = 0 \Rightarrow x = 4\) \(f(4) = 4(4) - \frac{1}{2}(4)^2 = 16 - 8 = 8\) \(f(-2) = 4(-2) - \frac{1}{2}(-2)^2 = -8 - 2 = -10\) \(f(\frac{9}{2}) = 4(\frac{9}{2}) - \frac{1}{2}(\frac{9}{2})^2 = 18 - \frac{81}{8} = \frac{144-81}{8} = \frac{63}{8} = 7.875\)…
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