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CUET · MATHS · PYQ PAPER 2024

Radiation of frequency \(2 v _0\) incident on a metal with threshold frequency \(v _0\) results in maximum kinetic energy of photoelectrons as :

  1. A No photoelectrons emitted
  2. B All have kinetic energy equal to \(hv _0\)
  3. C Maximum kinetic energy can be \(hv _0\)
  4. D Maximum kinetic energy will be \(2 hv _0\)
Verified Solution

Answer & Solution

Correct Answer

(C) Maximum kinetic energy can be \(hv _0\)

Step-by-step Solution

Detailed explanation

Solution \(K_{max} = hf - hf_0\) \(K_{max} = h(2v_0) - h(v_0)\) \(K_{max} = hv_0\)
From CUET
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