ExamBro
ExamBro
CUET · MATHS · PYQ PAPER 2025

Probability distribution of random variable \(X\) is
X-2-1012
P(X)2/111/114/113/111/11
Then the value of \(E(X)\) is

  1. A 0
  2. B \(\frac{10}{11}\)
  3. C \(-\frac{10}{11}\)
  4. D \(\frac{11}{10}\)
Verified Solution

Answer & Solution

Correct Answer

(A) 0

Step-by-step Solution

Detailed explanation

\(E(X) = \sum x P(X=x)\) \(E(X) = (-2)\left(\frac{2}{11}\right) + (-1)\left(\frac{1}{11}\right) + (0)\left(\frac{4}{11}\right) + (1)\left(\frac{3}{11}\right) + (2)\left(\frac{1}{11}\right)\) \(E(X) = \frac{-4}{11} - \frac{1}{11} + 0 + \frac{3}{11} + \frac{2}{11}\)…
From CUET
Explore more questions on app