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CUET · MATHS · PYQ PAPER 2025

Particular solution of the differential equation \(x\left(1+y^2\right) d x-y\left(1+x^2\right) d y=0\), given that \(y=0\) when \(x=1\), is:

  1. A \(\left(1+x^2\right)=2\left(1+y^2\right)\)
  2. B \(\left(1+y^2\right)=2\left(1+x^2\right)\)
  3. C \(\left(1+x^2\right)=4\left(1+y^2\right)\)
  4. D \(\left(1+y^2\right)=4\left(1+x^2\right)\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\left(1+x^2\right)=2\left(1+y^2\right)\)

Step-by-step Solution

Detailed explanation

\(\frac{x}{1+x^2} d x = \frac{y}{1+y^2} d y\) \(\int \frac{x}{1+x^2} d x = \int \frac{y}{1+y^2} d y\) \(\frac{1}{2} \ln \left(1+x^2\right) = \frac{1}{2} \ln \left(1+y^2\right) + C_1\) \(\ln \left(1+x^2\right) = \ln \left(1+y^2\right) + C\) Given \(y=0\) when \(x=1\):…
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