CUET · MATHS · PYQ PAPER 2023
Objective function \(z=200 x+500 y\), subject to the constraints
\(x+2 y \geq 10, \quad 3 x+4 y \leq 24, \quad x \geq 0, \quad y \geq 0\),
the minimum value of \(z\) is :
- A 2500
- B 3000
- C \(0\)
- D 2300
Answer & Solution
Correct Answer
(D) 2300
Step-by-step Solution
Detailed explanation
Vertices of the feasible region: \(x=0, x+2y=10 \Rightarrow (0,5)\) \(x=0, 3x+4y=24 \Rightarrow (0,6)\) \(x+2y=10, 3x+4y=24 \Rightarrow (4,3)\) Evaluate \(z=200 x+500 y\) at vertices: \(z(0,5) = 200(0)+500(5) = 2500\) \(z(0,6) = 200(0)+500(6) = 3000\)…
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