CUET · MATHS · PYQ PAPER 2023
Maximize \(z=2 x-y\)
Subject to constraints
\(x+y \leq 4, \quad x+3 y \leq 6, \quad x \geq 0, \quad y \geq 0 .\)
The corner points of the feasible region are:
- A \((0,4),(4,0),(0,0),(2,3)\)
- B \((0,2),(6,0),(0,0),(1,2)\)
- C \((0,2),(4,0),(0,0),(3,1)\)
- D \((0,2),(4,0),(0,0),(1,3)\)
Answer & Solution
Correct Answer
(C) \((0,2),(4,0),(0,0),(3,1)\)
Step-by-step Solution
Detailed explanation
\(x=0, y=0 \implies (0,0)\) \(x=0, x+3y=6 \implies 3y=6 \implies y=2 \implies (0,2)\) \(y=0, x+y=4 \implies x=4 \implies (4,0)\) \(x+y=4, x+3y=6 \implies (x+3y)-(x+y)=6-4 \implies 2y=2 \implies y=1 \implies x+1=4 \implies x=3 \implies (3,1)\) The corner points of the feasible…
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