CUET · MATHS · PYQ PAPER 2025
Match List-l with List-ll
| List-l (Mathematical Statement) | List-ll (Value) |
| (A) \(\hat{i} \cdot(\hat{j} \times \hat{k})\) | (I) \(-\hat{k}\) |
| (B) \(\hat{j} \cdot(\hat{i} \times \hat{k})\) | (II) 1 |
| (C) \(\hat{i} \times(\hat{j} \times \hat{k})\) | (III) \(-1\) |
| (D) \(\hat{j} \times \hat{i}\) | (IV) \(\overrightarrow{0}\) |
- A (A) - (II), (B) - (III), (C) - (IV), (D) - (I)
- B (А) - (III), (В) - (IV), (C) - (I), (D) - (II)
- C (A) - (IV), (B) - (III), (C) - (I), (D) - (II)
- D (А) - (I), (B) - (II), (С) - (III), (D) - (IV)
Answer & Solution
Correct Answer
(A) (A) - (II), (B) - (III), (C) - (IV), (D) - (I)
Step-by-step Solution
Detailed explanation
(A) \(\hat{i} \cdot(\hat{j} \times \hat{k}) = \hat{i} \cdot \hat{i} = 1\) (A) matches (II) (B) \(\hat{j} \cdot(\hat{i} \times \hat{k}) = \hat{j} \cdot (-\hat{j}) = -1\) (B) matches (III) (C) \(\hat{i} \times(\hat{j} \times \hat{k}) = \hat{i} \times \hat{i} = \overrightarrow{0}\)…
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