CUET · MATHS · PYQ PAPER 2023
Match List-l with List-ll
| List-l | List-II |
| (A) \(\lim _{x \rightarrow 0} \frac{1-\cos 2 x}{x}\) | (I) \(\frac{5}{2}\) |
| (B) \(\lim _{x \rightarrow 0} \frac{\sin 2 x}{x}\) | (II) 5 |
| (C) \(\lim _{x \rightarrow 1} \frac{x^5-1}{x^2-1}\) | (III) 2 |
| (D) \(\lim _{x \rightarrow 0} \frac{(x+1)^5-1}{x}\) | (IV) 0 |
Choose the correct answer from the options given below:
- A (A)-(III),(B)-(I),(C)-(II),(D)-(IV)
- B (A)-(IV),(B)-(III),(C)-(I),(D)-(II)
- C (A)-(I),(B)-(II),(C)-(IV),(D)-(III)
- D (A)-(II),(B)-(IV),(C)-(III),(D)-(I)
Answer & Solution
Correct Answer
(B) (A)-(IV),(B)-(III),(C)-(I),(D)-(II)
Step-by-step Solution
Detailed explanation
(A) \( \lim _{x \rightarrow 0} \frac{1-\cos 2 x}{x} = \lim _{x \rightarrow 0} \frac{2\sin^2 x}{x} = \lim _{x \rightarrow 0} 2 \cdot \frac{\sin x}{x} \cdot \sin x = 2 \cdot 1 \cdot 0 = 0 \). (A) matches (IV). (B)…
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