CUET · MATHS · PYQ PAPER 2025
Match List-l with List-ll
| List - l (Inverse Trigonometric function) | List - ll (Principal values of arguments) |
| (A) \(\sin ^{-1}\left(-\frac{1}{2}\right)\) | (I) \(-\frac{\pi}{3}\) |
| (B) \(\cos ^{-1}\left(-\frac{1}{2}\right)\) | (II) \(\frac{3 \pi}{4}\) |
| (C) \(\tan ^{-1}(-\sqrt{3})\) | (III) \(-\frac{\pi}{6}\) |
| (D) \(\sec ^{-1}(-\sqrt{2})\) | (IV) \(\frac{2 \pi}{3}\) |
- A (A) – (III), (B) – (IV), (C) - (I), (D) – (II)
- B (A) - (III), (B) – (IV), (C) - (II), (D) – (I)
- C A) - (IV), (B) - (III), (C) - (II), (D) – (I)
- D (A) - (IV), (B) – (III), (C) – (I), (D) – (II)
Answer & Solution
Correct Answer
(A) (A) – (III), (B) – (IV), (C) - (I), (D) – (II)
Step-by-step Solution
Detailed explanation
(A) \( \sin^{-1}\left(-\frac{1}{2}\right) = -\frac{\pi}{6} \). Matches (III). (B) \( \cos^{-1}\left(-\frac{1}{2}\right) = \pi - \cos^{-1}\left(\frac{1}{2}\right) = \pi - \frac{\pi}{3} = \frac{2\pi}{3} \). Matches (IV). (C)…
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