CUET · MATHS · PYQ PAPER 2025
Match List-I with List-II
| List-I (Matrix) | List-II (Inverse of the Matrix) |
| (A) \(\left[\begin{array}{cc}1 & 7 \\ 4 & -2\end{array}\right]\) | (I) \(\left[\begin{array}{cc}2 / 15 & 1 / 10 \\ -1 / 15 & 1 / 5\end{array}\right]\) |
| (B) \(\left[\begin{array}{cc}6 & -3 \\ 2 & 4\end{array}\right]\) | (II) \(\left[\begin{array}{cc}1 / 5 & -2 / 15 \\ -1 / 10 & 7 / 30\end{array}\right]\) |
| (C) \(\left[\begin{array}{cc}5 & 2 \\ -5 & 4\end{array}\right]\) | (III) \(\left[\begin{array}{cc}\frac{1}{15} & \frac{7}{30} \\ 2 / 15 & -1 / 30\end{array}\right]\) |
| (D) \(\left[\begin{array}{ll}7 & 4 \\ 3 & 6\end{array}\right]\) | IV) \(\left[\begin{array}{cc}2 / 15 & -1 / 15 \\ 1 / 6 & 1 / 6\end{array}\right]\) |
- A \((A) - (I), (B) - (II), (C) - (III), (D) - (IV)\)
- B \((A) - (I), (B) - (III), (C) - (II), (D) - (IV)\)
- C \((A) - (III), (B) - (I), (C) - (IV), (D) - (II)\)
- D \((A) - (III), (B) - (IV), (C) - (I), (D) - (II)\)
Answer & Solution
Correct Answer
(C) \((A) - (III), (B) - (I), (C) - (IV), (D) - (II)\)
Step-by-step Solution
Detailed explanation
\(A^{-1} = \frac{1}{(1)(-2)-(7)(4)} \left[\begin{array}{cc}-2 & -7 \\ -4 & 1\end{array}\right] = \frac{1}{-30} \left[\begin{array}{cc}-2 & -7 \\ -4 & 1\end{array}\right] = \left[\begin{array}{cc}1/15 & 7/30 \\ 2/15 & -1/30\end{array}\right]\) (A) - (III)…
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