ExamBro
ExamBro
CUET · MATHS · PYQ PAPER 2025

Match List - I with List - II
List - I (Matrix/Equations)List - II (Values)
(A) \(\left[\begin{array}{cc}2 x+1 & 3 y \\ 0 & y^2-5 y\end{array}\right]=\left[\begin{array}{cc}x+3 & y^2+2 \\ 0 & -6\end{array}\right]\)(I) \(x = 2, y = - 1\)
(B) \(\left[\begin{array}{ccc}1 & 2 & -1 \\ x & 0 & 3 \\ y & 3 & 4\end{array}\right]\) is symmetric(II) \(x = 2, y = 2\)
(C) \(\left[\begin{array}{ll}x & 1\end{array}\right]\left[\begin{array}{cc}1 & 0 \\ -2 & -3\end{array}\right]\left[\begin{array}{ll}5 & 2 \\ 0 & y\end{array}\right]=0\)(III) \(x = - 2, y = 2\)
(D) \(\left[\begin{array}{ll}x & 0 \\ 1 & 1\end{array}\right]\left[\begin{array}{ll}x & 0 \\ 1 & 1\end{array}\right]=\left[\begin{array}{cc}4 & 0 \\ -1 & y / 2\end{array}\right]\)(IV) \(x = 2, y = 0\)
Choose the correct answer from the options given below:

  1. A (A) - (II), (B) - (I), (C) - (IV), (D) - (III)
  2. B (А) - (I), (В) - (II), (C) - (III), (D) - (IV)
  3. C (А) - (III), (В) - (IV), (C) - (I), (D) - (II)
  4. D (A) - (IV), (B) - (III), (С) - (II), (D) - (I)
Verified Solution

Answer & Solution

Correct Answer

(A) (A) - (II), (B) - (I), (C) - (IV), (D) - (III)

Step-by-step Solution

Detailed explanation

(A) \(2x+1=x+3 \Rightarrow x=2\) \(3y=y^2+2 \Rightarrow y^2-3y+2=0 \Rightarrow (y-1)(y-2)=0 \Rightarrow y=1, 2\) \(y^2-5y=-6 \Rightarrow y^2-5y+6=0 \Rightarrow (y-2)(y-3)=0 \Rightarrow y=2, 3\) \(y=2\) \((A) \rightarrow (II)\) (B) \(a_{21}=a_{12} \Rightarrow x=2\)…
From CUET
Explore more questions on app