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CUET · MATHS · PYQ PAPER 2023

Match List I with List II
List - I List - II
(A) \(|\vec{a} \times \hat{i}|^2+|\vec{a} \times \hat{j}|^2+|\vec{a} \times \hat{k}|^2\)=(I) \(|\vec{a}|^2\)
(B) \(\frac{(\vec{a} \cdot \vec{b})^2+|\vec{a} \times \vec{b}|^2}{|\vec{b}|^2}=\)(II) \(\sqrt{3}|\vec{a}|\)
(C) \(\vec{a}, \vec{b}\) and \(\vec{c}\) are three mutually perpendicular vectors of equal magnitude then \(|\vec{a}+\vec{b}+\vec{c}|=\) (III) \(\frac{1}{2}|\vec{a} \times \vec{b}|\)
(D) Area of parallelogram with diagonals \(\vec{a}\) and \(\vec{b}\)(IV) \(2|\vec{a}|^2\)
Choose the correct answer from the options given below:

  1. A А - І, В - II, С - II, D - IV
  2. B А - II, В - ІІІ, C - IV, D - I
  3. C А - III, B - IV, C - II, D - I
  4. D A - IV, B - I, C - II, D - III
Verified Solution

Answer & Solution

Correct Answer

(D) A - IV, B - I, C - II, D - III

Step-by-step Solution

Detailed explanation

(A) \(|\vec{a} \times \hat{i}|^2 + |\vec{a} \times \hat{j}|^2 + |\vec{a} \times \hat{k}|^2 = (|\vec{a}|^2 - (\vec{a} \cdot \hat{i})^2) + (|\vec{a}|^2 - (\vec{a} \cdot \hat{j})^2) + (|\vec{a}|^2 - (\vec{a} \cdot \hat{k})^2) \)…
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