CUET · MATHS · PYQ PAPER 2023
Match List I with List II
| List - I | List - II |
| (A) \(|\vec{a} \times \hat{i}|^2+|\vec{a} \times \hat{j}|^2+|\vec{a} \times \hat{k}|^2\)= | (I) \(|\vec{a}|^2\) |
| (B) \(\frac{(\vec{a} \cdot \vec{b})^2+|\vec{a} \times \vec{b}|^2}{|\vec{b}|^2}=\) | (II) \(\sqrt{3}|\vec{a}|\) |
| (C) \(\vec{a}, \vec{b}\) and \(\vec{c}\) are three mutually perpendicular vectors of equal magnitude then \(|\vec{a}+\vec{b}+\vec{c}|=\) | (III) \(\frac{1}{2}|\vec{a} \times \vec{b}|\) |
| (D) Area of parallelogram with diagonals \(\vec{a}\) and \(\vec{b}\) | (IV) \(2|\vec{a}|^2\) |
- A А - І, В - II, С - II, D - IV
- B А - II, В - ІІІ, C - IV, D - I
- C А - III, B - IV, C - II, D - I
- D A - IV, B - I, C - II, D - III
Answer & Solution
Correct Answer
(D) A - IV, B - I, C - II, D - III
Step-by-step Solution
Detailed explanation
(A) \(|\vec{a} \times \hat{i}|^2 + |\vec{a} \times \hat{j}|^2 + |\vec{a} \times \hat{k}|^2 = (|\vec{a}|^2 - (\vec{a} \cdot \hat{i})^2) + (|\vec{a}|^2 - (\vec{a} \cdot \hat{j})^2) + (|\vec{a}|^2 - (\vec{a} \cdot \hat{k})^2) \)…
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