CUET · MATHS · PYQ PAPER 2025
Match List-I with List-II
| List-I | List-II |
| (A) The minimum value of \(f(x)=(2 x-1)^2+3\) | (I) 4 |
| (B) The maximum value of \(f(x)=-|x+1|+4\) | (II) 10 |
| (C) The minimum value of \(f(x)=\sin (2 x)+6\) | (III) 3 |
| (D) The maximum value of \(f(x)=-(x-1)^2+10\) | (IV) 5 |
- A \((A) - (I), (B) - (II), (C) - (III), (D) - (IV)\)
- B \((A) - (III), (B) - (II), (C) - (I), (D) - (IV)\)
- C \((A) - (III), (B) - (I), (C) - (IV), (D) - (II)\)
- D \((A) - (III), (B) - (IV), (C) - (I), (D) - (II)\)
Answer & Solution
Correct Answer
(C) \((A) - (III), (B) - (I), (C) - (IV), (D) - (II)\)
Step-by-step Solution
Detailed explanation
(A) \((2x-1)^2 \ge 0 \Rightarrow \min((2x-1)^2) = 0\) \(f(x)_{\min} = 0 + 3 = 3\) (B) \(|x+1| \ge 0 \Rightarrow \max(-|x+1|) = 0\) \(f(x)_{\max} = 0 + 4 = 4\) (C) \(\min(\sin(2x)) = -1\) \(f(x)_{\min} = -1 + 6 = 5\) (D) \((x-1)^2 \ge 0 \Rightarrow \max(-(x-1)^2) = 0\)…
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