CUET · MATHS · PYQ PAPER 2025
Match List-I with List-II
| List-I | List-II |
| (A) \(f ( x )=| x |\) | (I) Not differentiable at \(x=-2\) only |
| (B) \(f(x)=|x+2|\) | (II) Not differentiable at \(x=0\) only |
| (C) \(f(x)=\left|x^2-4\right|\) | (III) Not differentiable at \(x=2\) only |
| (D) \(f(x)=|x-2|\) | (IV) Not differentiable at \(x=2,-2\) only |
- A \((A) - (I), (B) - (II), (C) - (III), (D) - (IV)\)
- B \((A) - (II), (B) - (I), (C) - (IV), (D) - (III)\)
- C \((A) - (II), (B) - (I), (C) - (III), (D) - (IV)\)
- D \((A) - (IV), (B) - (III), (C) - (II), (D) - (I)\)
Answer & Solution
Correct Answer
(B) \((A) - (II), (B) - (I), (C) - (IV), (D) - (III)\)
Step-by-step Solution
Detailed explanation
(A) \(f(x)=|x|\) is not differentiable at \(x=0\). Matches (II). (B) \(f(x)=|x+2|\) is not differentiable at \(x=-2\). Matches (I). (C) \(f(x)=|x^2-4|\) is not differentiable at \(x^2-4=0 \Rightarrow x=\pm2\). Matches (IV). (D) \(f(x)=|x-2|\) is not differentiable at \(x=2\).…
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