CUET · MATHS · PYQ PAPER 2025
Match List - I with List - II
| List - I | List - II |
| (A) Line: x = 2y + 1 = z - 1 | (I) Crosses xz-plane at (1,0,1) |
| (B) Line: x + 1 = 2y + 1 = z | (II) Crosses xz-plane at (0,0,1) |
| (C) Line: x - 1 = 2y = z + 1 | (III) Crosses xz-plane at (1,0,-1) |
| (D) Line: x - 1 = 2y = z - 1 | (IV) Crosses xz-plane at (1,0,2) |
- A (A) - (IV), (Β) - (II), (C) - (III), (D) - (I)
- B (А) - (I), (В) - (IV), (C) - (III), (D) - (I)
- C (A) - (IV), (B) - (III), (С) - (II), (D) - (I)
- D (А) - (II), (В) - (III), (C) - (IV), (D) - (I)
Answer & Solution
Correct Answer
(A) (A) - (IV), (Β) - (II), (C) - (III), (D) - (I)
Step-by-step Solution
Detailed explanation
(A) Line: \(x = 2y + 1 = z - 1\) Crosses xz-plane when \(y = 0\): \(x = 2(0) + 1 = 1\) \(z - 1 = 1 \implies z = 2\) Point: \((1, 0, 2)\). Matches (IV). (B) Line: \(x + 1 = 2y + 1 = z\) Crosses xz-plane when \(y = 0\): \(x + 1 = 2(0) + 1 \implies x + 1 = 1 \implies x = 0\)…
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