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CUET · MATHS · PYQ PAPER 2025

Match List-I with List-II
List-IList-II
(A) If A is a non singular matrix of order n, then \(| A (\operatorname{adjA})|\) is equal to(I) \(|A|^{n-1}\)
(B) If A is a non singular matrix of order n, then |adj(adj A)| is equal to(II) \(|A|^{n-2} A\)
(C) If A is a non singular matrix of order n, then \(\operatorname{adj}(\operatorname{adj} A )\) is equal to(III) \(|A|^n\)
(D) if A is a non singular matrix of order n, then \(|(\operatorname{adj} A)|\) is equal to(IV) \(|A|^{(n-1)^2}\)
Choose the correct answer from the options given below :

  1. A (A) - (I), (B) - (II), (С) - (III), (D) – (IV)
  2. B (А) - (II), (B) – (I), (C) - (III), (D) - (IV)
  3. C (А) - (III), (В) - (IV), (C) - (II), (D) - (I)
  4. D (А) - (III), (В) - (IV), (C) - (I), (D) - (II)
Verified Solution

Answer & Solution

Correct Answer

(C) (А) - (III), (В) - (IV), (C) - (II), (D) - (I)

Step-by-step Solution

Detailed explanation

(A) \(| A (\operatorname{adjA})| = ||A|I| = |A|^n |I| = |A|^n\) Match: (III) (B) \(|\operatorname{adj}(\operatorname{adj} A)| = |\operatorname{adj} A|^{n-1} = (|A|^{n-1})^{n-1} = |A|^{(n-1)^2}\) Match: (IV) (C) \(\operatorname{adj}(\operatorname{adj} A ) = |A|^{n-2} A\) Match:…
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