CUET · MATHS · PYQ PAPER 2023
Match List I with List II
| LIST-I | LIST-II |
| A. \(\left[1 + \left(\frac{dy}{dx}\right)^2\right] = \frac{d^2y}{dx^2}\) | I. order 2, degree 3 |
| B. \(\left(\frac{d^3y}{dx^3}\right)^2 - 3\frac{d^2y}{dx^2} + 2\left(\frac{dy}{dx}\right)^4 = y^4\) | II. order 2, degree 1 |
| C. \(\left(\frac{dy}{dx}\right)^2 + \left(\frac{d^2y}{dx^2}\right)^3 = 0\) | III. order 1, degree 2 |
| D. \(\left(\frac{dy}{dx}\right)^2 + 6y^3 = 0\) | IV. order 3, degree 2 |
Choose the correct answer from the options given below:
- A A-I, B-III, C-IV, D-II
- B A-III, B-I, C-II, D-IV
- C A-IV, B-II, C-III, D-I
- D A-II, B-IV, C-I, D-III
Answer & Solution
Correct Answer
(D) A-II, B-IV, C-I, D-III
Step-by-step Solution
Detailed explanation
A. \( \left[1 + \left(\frac{dy}{dx}\right)^2\right] = \frac{d^2y}{dx^2} \) : Order 2, Degree 1 (II) B. \( \left(\frac{d^3y}{dx^3}\right)^2 - 3\frac{d^2y}{dx^2} + 2\left(\frac{dy}{dx}\right)^4 = y^4 \) : Order 3, Degree 2 (IV) C.…
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