CUET · MATHS · PYQ PAPER 2023
Match List - I with List - II.
| LIST - I | LIST - II |
| (A) \((\hat{i} \times \hat{j})+(\hat{j} \times \hat{i})\) | (I) 1 |
| (B) \(\hat{i} \cdot \hat{i}+\hat{j} \cdot \hat{j}+\hat{k} \cdot \hat{k}\) | (II) \(\hat{k}-\hat{j}\) |
| (C) \(\hat{i} \times(\hat{i}+\hat{j}+\hat{k})\) | (III) \(\overrightarrow{0}\) |
| (D) \(\hat{i} \cdot(\hat{i}+\hat{j}+\hat{k})\) | (IV) 3 |
- A (A)-(II), (B)-(IV), (C)-(III), (D)-(I)
- B (A)-(III), (B)-(IV), (C)-(II), (D)-(I)
- C (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
- D (A)-(II), (B)-(IV), (C)-(I), (D)-(III)
Answer & Solution
Correct Answer
(B) (A)-(III), (B)-(IV), (C)-(II), (D)-(I)
Step-by-step Solution
Detailed explanation
(A) \((\hat{i} \times \hat{j})+(\hat{j} \times \hat{i}) = \hat{k} - \hat{k} = \overrightarrow{0}\) (III) (B) \(\hat{i} \cdot \hat{i}+\hat{j} \cdot \hat{j}+\hat{k} \cdot \hat{k} = 1+1+1 = 3\) (IV) (C)…
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