CUET · MATHS · PYQ PAPER 2023
Match List - I with List - II.
| LIST I | LIST II |
| A. \(\left[1+\left(\frac{d y}{d x}\right)^2\right]=\left(\frac{d^2 y}{d x^2}\right)^2\) | I. order \(=2\), degree \(=2\) |
| B. \(\frac{d^3 y}{d x^3}-3 \frac{d^2 y}{d x^2}+2\left(\frac{d y}{d x}\right)^4=y^4\) | II. order \(=3\), degree \(=2\) |
| C. \(\left(1+\frac{d y}{d x}\right)^3=\left(\frac{d^3 y}{d x^3}\right)^2\) | III. order \(=2\), degree \(=1\) |
| D. \(\left[1+\left(\frac{d y}{d x}\right)^2\right]^?=\frac{d^2 y}{d x^2}\) | IV. order \(=3\), degree \(=1\) |
- A (A)-(I), (B)-(IV), (C)-(II), (D)-(III)
- B (A)-(II), (B)-(III), (C)-(IV), (D)-(I)
- C (A)-(III), (B)-(II), (C)-(IV), (D)-(I)
- D (A)-(I), (B)-(IV), (C)-(III), (D)-(II)
Answer & Solution
Correct Answer
(A) (A)-(I), (B)-(IV), (C)-(II), (D)-(III)
Step-by-step Solution
Detailed explanation
A. \(\left[1+\left(\frac{d y}{d x}\right)^2\right]=\left(\frac{d^2 y}{d x^2}\right)^2\): Order \(=2\), Degree \(=2\). (Matches I) B. \(\frac{d^3 y}{d x^3}-3 \frac{d^2 y}{d x^2}+2\left(\frac{d y}{d x}\right)^4=y^4\): Order \(=3\), Degree \(=1\). (Matches IV) C.…
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