CUET · MATHS · PYQ PAPER 2025
Match List-I with List-II
| List - I | List - II |
| (A) Point of minima of \(f(x)=|x+1|\) | (I) 1 |
| (B) Minimum value of \(f(x)=|x|\) | (II) -1 |
| (C) Maximum value of \(f(x)=1-x^2\) | (III) 2 |
| (D) Minimum value of \(f(x)=2+\sin ^2 x\) | (IV) 0 |
- A (A) - (IV), (B) - (II), (C) - (III), (D) - (I)
- B (A) - (II), (B) - (IV), (C) - (I), (D) - (III)
- C (A) - (I), (B) - (III), (C) - (II), (D) - (IV)
- D (A) - (III), (B) - (I), (C) - (IV), (D) - (II)
Answer & Solution
Correct Answer
(B) (A) - (II), (B) - (IV), (C) - (I), (D) - (III)
Step-by-step Solution
Detailed explanation
(A) For \(f(x)=|x+1|\), minima occurs when \(x+1=0 \Rightarrow x=-1\). (A) - (II) (B) For \(f(x)=|x|\), minimum value is \(|0|=0\). (B) - (IV) (C) For \(f(x)=1-x^2\), maximum value occurs when \(x^2\) is minimum, i.e., \(x^2=0\). So, max value \( = 1-0 = 1\). (C) - (I) (D) For…
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