CUET · MATHS · PYQ PAPER 2025
Match List-I with List-II
| List - I | List - II |
| (A) \(\sin ^{-1}(-1)\) | (I) \(\frac{5 \pi}{6}\) |
| (B) \(\cot ^{-1}(-1)\) | (II) \(-\frac{\pi}{2}\) |
| (C) \(\sec ^{-1}\left(-\frac{2}{\sqrt{3}}\right)\) | (III) \(\frac{\pi}{4}\) |
| (D) \(\tan ^{-1}(1)\) | (IV) \(\frac{3 \pi}{4}\) |
- A (A) - (II), (B) - (IV), (C) - (I), (D) - (III)
- B (A) - (II), (B) - (III), (C) - (I), (D) - (IV)
- C (A) - (I), (B) - (IV), (C) - (II), (D) - (III)
- D (A) - (I), (B) - (III), (C) - (II), (D) - (IV)
Answer & Solution
Correct Answer
(A) (A) - (II), (B) - (IV), (C) - (I), (D) - (III)
Step-by-step Solution
Detailed explanation
(A) \(\sin^{-1}(-1) = -\frac{\pi}{2}\) (B) \(\cot^{-1}(-1) = \pi - \cot^{-1}(1) = \pi - \frac{\pi}{4} = \frac{3\pi}{4}\) (C) \(\sec^{-1}\left(-\frac{2}{\sqrt{3}}\right) = \pi - \sec^{-1}\left(\frac{2}{\sqrt{3}}\right) = \pi - \frac{\pi}{6} = \frac{5\pi}{6}\) (D)…
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