CUET · MATHS · PYQ PAPER 2025
Match List-I with List-II
| List-I (Inverse Trigonometric Function) | List-II (Principal Value) |
| (A) \(\sin ^{-1}\left(-\frac{1}{2}\right)\) | (I) \(\pi / 6\) |
| (B) \(\cos ^{-1}\left(-\frac{1}{2}\right)\) | (II) \(-\pi / 6\) |
| (C) \(\tan ^{-1}(-\sqrt{3})\) | (III) \(2 \pi / 3\) |
| (D) \(\cot ^{-1}(\sqrt{3})\) | (IV) \(-\pi / 3\) |
- A (A) - (IV), (B) - (I), (C) - (II), (D) - (III)
- B (А) - (I), (Β) - (II), (C) - (III), (D) - (IV)
- C (А) - (II), (В) - (III), (C) - (IV), (D) - (I)
- D (А) - (III), (В) - (IV), (C) - (I), (D) - (II)
Answer & Solution
Correct Answer
(C) (А) - (II), (В) - (III), (C) - (IV), (D) - (I)
Step-by-step Solution
Detailed explanation
(A) \(\sin^{-1}\left(-\frac{1}{2}\right) = -\sin^{-1}\left(\frac{1}{2}\right) = -\frac{\pi}{6}\) (B) \(\cos^{-1}\left(-\frac{1}{2}\right) = \pi - \cos^{-1}\left(\frac{1}{2}\right) = \pi - \frac{\pi}{3} = \frac{2\pi}{3}\) (C)…
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