CUET · MATHS · PYQ PAPER 2025
Match List-I with List-II
| List-I (Integral) | List-II (Value) |
| (A) \(\int_{-1}^1(|x|+1) d x\) | (I) 0 |
| (B) \(\int_{-2}^2|x+1| d x\) | (II) 2 |
| (C) \(\int_{-1}^1 3|x|^2 d x\) | (III) 5 |
| (D) \(\int_{-1}^1 x|x| d x\) | (IV) 3 |
Choose the Correct answer from the options given below :
- A (A) - (I), (B) - (IV), (C) - (III), (D) - (II)
- B (A) - (II), (B) - (III), (C) - (IV), (D) - (I)
- C (A) - (III), (B) - (IV), (C) - (I), (D) - (II)
- D (A) - (IV), (B) - (III), (C) - (II), (D) - (I)
Answer & Solution
Correct Answer
(D) (A) - (IV), (B) - (III), (C) - (II), (D) - (I)
Step-by-step Solution
Detailed explanation
(A) \(\int_{-1}^1(|x|+1) d x = 2 \int_0^1(x+1) d x\) \(2 \left[ \frac{x^2}{2} + x \right]_0^1 = 2 \left( \frac{1}{2} + 1 \right) = 3\) (B) \(\int_{-2}^2|x+1| d x = \int_{-2}^{-1}-(x+1) d x + \int_{-1}^2(x+1) d x\)…
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