ExamBro
ExamBro
CUET · MATHS · PYQ PAPER 2025

Match List-I with List-II
List-I (Function)List-II (Property)
(A) \(f(x)=\left\{\begin{array}{ll}\frac{x}{|x|} & : x \neq 0 \\ 0 & : x=0\end{array}\right.\)(I) continuous but not differentiable at  \(x=0\)
(B) \(f ( x )=| x |\)(II) continuous but not differentiable at \(x=1\)
(C) \(f(x)=\left|x^2-1\right|\)(III) discontinuous at \(x=0\)
(D) \(f(x)=|x-1|\)(IV) continuous but not differentiable at \(x=1,-1\)
Choose the correct answer from the options given below:

  1. A (A) - (III), (B) - (I), (C) - (IV), (D) - (II)
  2. B (A) - (IV), (B) - (I), (C) - (II), (D) - (III)
  3. C (A) - (III), (B) - (I), (C) - (II), (D) - (IV)
  4. D (A) - (IV), (B) - (III), (C) - (I), (D) - (II)
Verified Solution

Answer & Solution

Correct Answer

(A) (A) - (III), (B) - (I), (C) - (IV), (D) - (II)

Step-by-step Solution

Detailed explanation

(A) \(f(x)=\left\{\begin{array}{ll}\frac{x}{|x|} & : x \neq 0 \\ 0 & : x=0\end{array}\right.\) \(\lim_{x \to 0^-} f(x) = \lim_{x \to 0^-} \frac{x}{-x} = -1\) \(\lim_{x \to 0^+} f(x) = \lim_{x \to 0^+} \frac{x}{x} = 1\) \(-1 \neq 1\), so \(f(x)\) is discontinuous at \(x=0\).…