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CUET · MATHS · PYQ PAPER 2025

match List - I with List - II
List - I (function)List - II (inceasing on the interval)
(A) f(x) = -\(x^2\) - 2x + 1(I) \((-\infty,-1)\)
(B) f(x) = \(x^2\) + 1(II) \((1, \infty)\)
(C) f(x) = \(x^2\) - 2x + 3(III) \((-\infty, 0)\)
(D) f(x) = \(- x^2\)(IV) \((0, \infty)\)
Choose the correct answert from the option given below :

  1. A (A) - (I), (B) - (IV), (C) - (II), (D) - (III)
  2. B (A) - (I), (B) - (II), (C) - (IV), (D) - (III)
  3. C (A) - (III), (B) - (II), (C) - (IV), (D) - (I)
  4. D (A) - (I), (B) - (II), (C) - (III), (D) - (IV)
Verified Solution

Answer & Solution

Correct Answer

(A) (A) - (I), (B) - (IV), (C) - (II), (D) - (III)

Step-by-step Solution

Detailed explanation

(A) f(x) = \(x^2\) - 2x + 1 \(f'(x) = 2x - 2\) \(2x - 2 > 0 \Rightarrow x > 1\) Increasing on \((1, \infty)\). Matches (II). (B) f(x) = \(x^2\) + 1 \(f'(x) = 2x\) \(2x > 0 \Rightarrow x > 0\) Increasing on \((0, \infty)\). Matches (IV). (C) f(x) = \(x^2\) - 2x + 3…