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CUET · MATHS · PYQ PAPER 2025

Match List-I with List-II
List-(I) FunctionLis-(II) Derivative
(A) \(y=\sin ^{-1} x+\sin ^{-1} \sqrt{1-x^2},|x|<1\)(I) \(\frac{d y}{d x}=\frac{1}{2 y-1}\)
(B) \(y=\sqrt{x+y}, x+y>0, y \neq \frac{1}{2}\)(II) \(\frac{d y}{d x}=10^x \log _e 10\)
(C) \(y=\log _{10} x, x>0\)(III) \(\frac{d y}{d x}=0\)
(D) \(y=10^*\)(IV) \(\frac{d y}{d x}=\frac{1}{x \log _e 10}\)
Choose the correct answer from the options given below:

  1. A \((A) - (III), (B) - (I), (C) - (IV), (D) - (II)\)
  2. B \((A)-(I),(B)-(I I I),(C)-(I I),(D)-(I V)\)
  3. C \((A) - (III), (B) - (II), (C) - (I), (D) - (IV)\)
  4. D \((A)-(I I)\), \((B)-(I)\), \((C)-(I I I)\), \((D)-(I V)\)
Verified Solution

Answer & Solution

Correct Answer

(A) \((A) - (III), (B) - (I), (C) - (IV), (D) - (II)\)

Step-by-step Solution

Detailed explanation

(A) \(y=\sin ^{-1} x+\sin ^{-1} \sqrt{1-x^2}\) For \(x \in (0,1)\), \(y=\sin ^{-1} x+\cos ^{-1} x = \frac{\pi}{2}\) \(\frac{dy}{dx} = 0\) (A) matches (III). (B) \(y=\sqrt{x+y}\) \(y^2 = x+y\) \(2y \frac{dy}{dx} = 1 + \frac{dy}{dx}\) \((2y-1) \frac{dy}{dx} = 1\)…
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