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CUET · MATHS · PYQ PAPER 2025

Match List-I with List-II
List-I (Differential equation)List-II (Order and degree)
(A) \(\left(y^{\prime \prime}\right)^3+\left(y^{\prime}\right)^4-6=\left(y^{\prime \prime \prime}\right)^2\)(I) Order \(=1\), Degree = 2
(B) \(\sqrt{\left(y^{\prime}\right)^2+5}=y^{\prime \prime}\)(II) Order \(=2\), Degree = 3
(C) \(\left(y^{\prime}\right)^2=\left(2+y^{\prime \prime}\right)^{3 / 2}\)(III) Order \(=2\), Degree = 2
(D) \(y=x y^{\prime}+\sqrt{a^2\left(y^{\prime}\right)^2+b^2}\)(IV) Order \(=3\), Degree = 2
Choose the correct answer from the options given below :

  1. A (A) - (II), (B) - (III), (C) - (IV), (D) - (I)
  2. B (A) - (IV), (B) - (I), (C) - (III), (D) - (II)
  3. C (A) - (IV), (B) - (III), (C) - (II), (D) - (I)
  4. D (A) - (IV), (B) - (I), (C) - (II), (D) - (III)
Verified Solution

Answer & Solution

Correct Answer

(C) (A) - (IV), (B) - (III), (C) - (II), (D) - (I)

Step-by-step Solution

Detailed explanation

For (A) \(\left(y^{\prime \prime}\right)^3+\left(y^{\prime}\right)^4-6=\left(y^{\prime \prime \prime}\right)^2\): Order = 3, Degree = 2. (A) - (IV) For (B) \(\sqrt{\left(y^{\prime}\right)^2+5}=y^{\prime \prime}\): \(\left(y^{\prime}\right)^2+5=\left(y^{\prime \prime}\right)^2\).…