CUET · MATHS · PYQ PAPER 2025
Match List-I with List-II
| List-I (Differential Equation) | List-II (Integrating Factor) |
| (A) \(\frac{d y}{d x}+2 x y=1\) | (I) \(x\) |
| (B) \(x \frac{d y}{d x}+2 x y=1\) | (II) \(e^{2 x}\) |
| (C) \(x \frac{d y}{d x}+y=1\) | (III) \(x^2\) |
| (D) \(x \frac{d y}{d x}+2 y=2\) | (IV) \(e^{x^2}\) |
- A (A) - (IV), (B) - (II), (C) - (III), (D) - (I)
- B (A) - (IV), (B) - (II), (C) - (I), (D) – (III)
- C (A) - (II), (B) - (I), (C) - (IV), (D) – (III)
- D (A) - (II), (B) - (III), (C) - (IV), (D) - (I)
Answer & Solution
Correct Answer
(B) (A) - (IV), (B) - (II), (C) - (I), (D) – (III)
Step-by-step Solution
Detailed explanation
(A) \(\frac{d y}{d x}+2 x y=1\) \(P(x) = 2x\) \(IF = e^{\int 2x dx} = e^{x^2}\) (A) \(\to\) (IV) (B) \(x \frac{d y}{d x}+2 x y=1 \implies \frac{d y}{d x}+2 y=\frac{1}{x}\) \(P(x) = 2\) \(IF = e^{\int 2 dx} = e^{2x}\) (B) \(\to\) (II) (C)…
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