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CUET · MATHS · PYQ PAPER 2023

Match List - I with List - II.
LIST I
Differential equation
LIST II
Integrating Factor (I.F)
A. \(\frac{d y}{d x}-\frac{y}{x}=2 x\)I. \(x^2-1\)
B. \(\frac{d y}{d x}+\left(\frac{2 x}{x^2-1}\right) y=\frac{2}{\left(x^2-1\right)^2}\)II. \(\sqrt{1-x^2}\)
C. \(\frac{d y}{d x}-\left(\frac{x}{1-x^2}\right) y=\frac{1}{1-x^2}\)III. \(\frac{1}{x}\)
D. \(\frac{d y}{d x}+\frac{2 x y}{1+x^2}=\frac{\cot x}{1+x^2}\)IV. \(1+x^2\)
Choose the correct answer from the options given below:

  1. A (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
  2. B (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
  3. C (A)-(III), (B)-(II), (C)-(I), (D)-(IV)
  4. D (A)-(III), (B)-(I), (C)-(II), (D)-(IV)
Verified Solution

Answer & Solution

Correct Answer

(D) (A)-(III), (B)-(I), (C)-(II), (D)-(IV)

Step-by-step Solution

Detailed explanation

A. \( P(x) = -\frac{1}{x} \) I.F. \( = e^{\int -\frac{1}{x} dx} = e^{-\ln|x|} = \frac{1}{x} \) A. Matches III. B. \( P(x) = \frac{2 x}{x^2-1} \) I.F. \( = e^{\int \frac{2 x}{x^2-1} dx} = e^{\ln|x^2-1|} = x^2-1 \) B. Matches I. C. \( P(x) = -\frac{x}{1-x^2} \) I.F.…