CUET · MATHS · PYQ PAPER 2023
Match List - I with List - II.
| LIST I Differential equation | LIST II Integrating Factor (I.F) |
| A. \(\frac{d y}{d x}-\frac{y}{x}=2 x\) | I. \(x^2-1\) |
| B. \(\frac{d y}{d x}+\left(\frac{2 x}{x^2-1}\right) y=\frac{2}{\left(x^2-1\right)^2}\) | II. \(\sqrt{1-x^2}\) |
| C. \(\frac{d y}{d x}-\left(\frac{x}{1-x^2}\right) y=\frac{1}{1-x^2}\) | III. \(\frac{1}{x}\) |
| D. \(\frac{d y}{d x}+\frac{2 x y}{1+x^2}=\frac{\cot x}{1+x^2}\) | IV. \(1+x^2\) |
- A (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
- B (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
- C (A)-(III), (B)-(II), (C)-(I), (D)-(IV)
- D (A)-(III), (B)-(I), (C)-(II), (D)-(IV)
Answer & Solution
Correct Answer
(D) (A)-(III), (B)-(I), (C)-(II), (D)-(IV)
Step-by-step Solution
Detailed explanation
A. \( P(x) = -\frac{1}{x} \) I.F. \( = e^{\int -\frac{1}{x} dx} = e^{-\ln|x|} = \frac{1}{x} \) A. Matches III. B. \( P(x) = \frac{2 x}{x^2-1} \) I.F. \( = e^{\int \frac{2 x}{x^2-1} dx} = e^{\ln|x^2-1|} = x^2-1 \) B. Matches I. C. \( P(x) = -\frac{x}{1-x^2} \) I.F.…
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