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CUET · MATHS · PYQ PAPER 2023

Match List - I with List - II. Evaluate the integrals.
\(List - I\)\(List - II\)
(A) \(\int_0^{\pi / 2} \frac{\sin x-\cos x}{1+\sin x \cos x} d x\)\((I)\) \(2 \pi\)
(B) \(\int_0^{1 / 2} \frac{d x}{\sqrt{x-x^2}}\)\((II)\) \(\frac{\pi}{4}\)
(C) \(\int_{-\pi}^\pi x \sin x d x\)\((III)\) \(0\)
(D) \(\int_0^1 \frac{1}{1+x^2} d x\)\((IV)\) \(\frac{\pi}{2}\)

  1. A \((A)-(I), (B)-(IV), (C)-(II), (D)-(III)\)
  2. B \((A)-(III), (B)-(IV), (C)-(I), (D)-(II)\)
  3. C \((A)-(III), (B)-(II), (C)-(I), (D)-(IV)\)
  4. D \((A)-(I), (B)-(III), (C)-(IV), (D)-(II)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \((A)-(III), (B)-(IV), (C)-(I), (D)-(II)\)

Step-by-step Solution

Detailed explanation

(A) \(I = \int_0^{\pi / 2} \frac{\sin x-\cos x}{1+\sin x \cos x} d x\) \(I = \int_0^{\pi / 2} \frac{\sin (\pi/2 - x)-\cos (\pi/2 - x)}{1+\sin (\pi/2 - x) \cos (\pi/2 - x)} d x = \int_0^{\pi / 2} \frac{\cos x-\sin x}{1+\cos x \sin x} d x = -I\) \(2I = 0 \Rightarrow I = 0\) (B)…