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CUET · MATHS · PYQ PAPER 2025

Match List-I with List-II
Consider two vectors \(\vec{a}=\hat{i}+2 \hat{j}-\hat{k}\) and \(\vec{b}=-3 \hat{i}-6 \hat{j}+3 \hat{k}\).
List-IList-II
(A) Angle between \(\vec{a}\) and \(\vec{b}\)(I) \(\cos ^{-1}\left(\frac{1}{\sqrt{6}}\right)\)
(B) Angle between \(\vec{a}\) and \(x\)-axis(II) \(\cos ^{-1}\left(\frac{2}{\sqrt{6}}\right)\)
(C) Angle between \(\vec{b}\) and \(x\)-axis(III) \(\pi\)
(D) Angle between \(\vec{a}\) and \(y\)-axis(IV) \(\cos ^{-1}\left(-\frac{1}{\sqrt{6}}\right)\)
Choose the correct answer from the options given below:

  1. A \((A)-(I I I),(B)-(I V),(C)-(I),(D)-(I I)\)
  2. B \((A)-(I I I),(B)-(I),(C)-(I V),(D)-(I I)\)
  3. C \((A)-(I I I),(B)-(I I),(C)-(I),(D)-(I V)\)
  4. D \((A)-(I I),(B)-(I I I),(C)-(I),(D)-(I V)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \((A)-(I I I),(B)-(I),(C)-(I V),(D)-(I I)\)

Step-by-step Solution

Detailed explanation

\( |\vec{a}| = \sqrt{1^2+2^2+(-1)^2} = \sqrt{6} \) \( |\vec{b}| = \sqrt{(-3)^2+(-6)^2+3^2} = \sqrt{9+36+9} = \sqrt{54} = 3\sqrt{6} \)…
From CUET
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