CUET · MATHS · PYQ PAPER 2023
Match List I with List II and choose the correct answer from the options given below:
| List - I | List - II |
| (A) \(\int \frac{\sin x}{1+\cos x} d x\) | (I) \(e^{\tan ^{-1} z}+C\) |
| (B) \(\int \frac{1}{1-\tan x} d x\) | (II) \(\log (\log x+1)+C\) |
| (C) \(\int \frac{e^{\tan ^{-1} x}}{1+x^2} d x\) | (III) \(-\log |1+\cos x|+C\) |
| (D) \(\int \frac{1}{x+x \log x} d x\) | (IV) \(\frac{x}{2}-\frac{1}{2} \log |\cos x-\sin x|+C\) |
- A A - II, B - III, C - IV, D - I
- B А - III, B - IV, C - I, D - II
- C А - І, В - ІІ, С - III, D - IV
- D A - IV, B - I, C - III, D - II
Answer & Solution
Correct Answer
(B) А - III, B - IV, C - I, D - II
Step-by-step Solution
Detailed explanation
(A) Let \(u = 1+\cos x\). Then \(du = -\sin x \, dx\). \(\int \frac{\sin x}{1+\cos x} dx = \int \frac{-du}{u} = -\log|u| + C = -\log|1+\cos x| + C\). (A) matches (III). (B) \(\int \frac{1}{1-\tan x} dx = \int \frac{\cos x}{\cos x - \sin x} dx\)…
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