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CUET · MATHS · PYQ PAPER 2025

Match List-I with List-II
An urn contains 4 white and 3 red balls. In a random draw of three balls, the probability of
List-IList-II
(A) No red ball is(I) \(\frac{12}{35}\)
(B) Only 1 red ball is(II) \(\frac{1}{35}\)
(C) Exactly 2 red balls is(III) \(\frac{4}{35}\)
(D) No white ball is(IV) \(\frac{18}{35}\)
Choose the correct answer from the options given below :

  1. A (A) - (III), (B) - (I), (C) - (II), (D) - (IV)
  2. B (A) - (III), (B) - (IV), (C) - (I), (D) - (II)
  3. C A) - (IV), (B) - (II), (C) - (I), (D) - (III)
  4. D (A) - (IV), (B) - (II), (C) - (III), (D) - (I)
Verified Solution

Answer & Solution

Correct Answer

(B) (A) - (III), (B) - (IV), (C) - (I), (D) - (II)

Step-by-step Solution

Detailed explanation

\( N_{total} = \binom{7}{3} = 35 \) (A) No red ball: \( P(A) = \frac{\binom{4}{3}}{\binom{7}{3}} = \frac{4}{35} \) (B) Only 1 red ball: \( P(B) = \frac{\binom{3}{1}\binom{4}{2}}{\binom{7}{3}} = \frac{3 \times 6}{35} = \frac{18}{35} \) (C) Exactly 2 red balls:…
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