CUET · MATHS · PYQ PAPER 2025
Match List 1 with List 2.
| List - 1 (Matrix) | List - 2 (Determinants) |
| (A) \(\operatorname{Matrix}(A)=\left[\begin{array}{cc}1 & 7 \\ -3 & 5\end{array}\right]\) | (I) 24 |
| (B) \(\operatorname{Matrix}(B)=\left[\begin{array}{cc}-2 & 5 \\ -3 & -3\end{array}\right]\) | (II) 32 |
| (C) \(\operatorname{Matrix}(C)=\left[\begin{array}{ll}-12 & 8 \\ -16 & 8\end{array}\right]\) | (III) 21 |
| (D) \(\operatorname{Matrix}(C)=\left[\begin{array}{ll}-12 & 8 \\ -16 & 8\end{array}\right]\) | (IV) 26 |
Choose the correct answer from the options given below :
- A (A) - (IV), (B) - (III), (C) - (I), (D) - (II)
- B (A) - (IV), (B) - (III), (C) - (II), (D) - (I)
- C (A) - (IV), (B) - (II), (C) - (I), (D) - (III)
- D (A) - (III), (B) - (IV), (C) - (I), (D) - (II)
Answer & Solution
Correct Answer
(B) (A) - (IV), (B) - (III), (C) - (II), (D) - (I)
Step-by-step Solution
Detailed explanation
\(\det(A) = (1)(5) - (7)(-3) = 5 + 21 = 26\) \(\det(B) = (-2)(-3) - (5)(-3) = 6 + 15 = 21\) \(\det(C) = (-12)(8) - (8)(-16) = -96 + 128 = 32\) (A) - (IV), (B) - (III), (C) - (II), (D) - (I)
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