CUET · MATHS · PYQ PAPER 2024
Magnetic moment of a thin bar magnet is ' M '. If it is bent into a semicircular form, its new magnetic moment will be
- A \(M / \pi\)
- B \(M / 2\)
- C M
- D \(2 M / \pi\)
Answer & Solution
Correct Answer
(D) \(2 M / \pi\)
Step-by-step Solution
Detailed explanation
\(M = mL\) \(L_{arc} = L = \pi R \Rightarrow R = L/\pi\) \(L_{eff} = 2R = 2L/\pi\) \(M' = m L_{eff} = m(2L/\pi)\) \(M' = (mL)(2/\pi) = 2M/\pi\)
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