CUET · MATHS · PYQ PAPER 2025
| List-1 | List-2 |
| (A) \(y=\sqrt{x^3}\) | (I) \(-1\) |
| (B) \(y=\sqrt{x}\) | (II) 1 |
| (C) \(y=x^3-47 x\) | (III) 1/4 |
| (D) \(x y=16\) | (IV) 3 |
- A (А) - (I), (Β) - (II), (С) - (III), (D) - (IV)
- B А) - (II), (В) - (I), (C) - (III), (D) - (IV)
- C (А) - (III), (В) - (IV), (C) - (II), (D) - (I)
- D (A) - (IV), (B) - (III), (C) - (II), (D) - (I)
Answer & Solution
Correct Answer
(D) (A) - (IV), (B) - (III), (C) - (II), (D) - (I)
Step-by-step Solution
Detailed explanation
(A) \(y=\sqrt{x^3}=x^{3/2}\) \(\frac{dy}{dx} = \frac{3}{2}x^{1/2}\) \(\frac{dy}{dx}\Big|_{x=4} = \frac{3}{2}\sqrt{4} = 3\) (A) - (IV) (B) \(y=\sqrt{x}=x^{1/2}\) \(\frac{dy}{dx} = \frac{1}{2}x^{-1/2}\) \(\frac{dy}{dx}\Big|_{x=4} = \frac{1}{2\sqrt{4}} = \frac{1}{4}\) (B) - (III)…
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