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CUET · MATHS · PYQ PAPER 2025

Let \(y=\cos \left(\sin x^2\right)\), then the value of \(\frac{d y}{d x}\) at \(x=\frac{\sqrt{\pi}}{2}\) is equal to

  1. A \(-\sqrt{\frac{\pi}{2}} \sin \left(\frac{1}{\sqrt{2}}\right)\)
  2. B \(-\frac{\sqrt{\pi}}{2} \sin \left(\frac{1}{\sqrt{2}}\right)\)
  3. C \(-\sqrt{\frac{\pi}{2}} \cos \left(\frac{1}{\sqrt{2}}\right)\)
  4. D \(\sqrt{\frac{\pi}{2}} \cos \left(\frac{1}{\sqrt{2}}\right)\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(-\sqrt{\frac{\pi}{2}} \sin \left(\frac{1}{\sqrt{2}}\right)\)

Step-by-step Solution

Detailed explanation

\( \frac{dy}{dx} = -\sin(\sin x^2) \cdot \cos x^2 \cdot 2x \) At \( x=\frac{\sqrt{\pi}}{2} \): \( \frac{dy}{dx} = -\sin\left(\sin \left(\frac{\sqrt{\pi}}{2}\right)^2\right) \cdot \cos \left(\frac{\sqrt{\pi}}{2}\right)^2 \cdot 2\left(\frac{\sqrt{\pi}}{2}\right) \)…