CUET · MATHS · PYQ PAPER 2025
Let \(x=t^2, y=t^3\). Then \(\frac{d^2 y}{d x^2}\) is equal to
- A \(\frac{3}{2}\)
- B \(\frac{3}{4 t}\)
- C 3t
- D \(\frac{3 t}{4}\)
Answer & Solution
Correct Answer
(B) \(\frac{3}{4 t}\)
Step-by-step Solution
Detailed explanation
\(\frac{dx}{dt} = 2t\) \(\frac{dy}{dt} = 3t^2\) \(\frac{dy}{dx} = \frac{dy/dt}{dx/dt} = \frac{3t^2}{2t} = \frac{3}{2}t\) \(\frac{d^2 y}{dx^2} = \frac{\frac{d}{dt}\left(\frac{dy}{dx}\right)}{\frac{dx}{dt}} = \frac{\frac{d}{dt}\left(\frac{3}{2}t\right)}{2t}\)…
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