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CUET · MATHS · PYQ PAPER 2025

Let \(X\) denotes the number of hours a person uses a mobile and the probability distribution of \(X\) is as :
X01234
P(X)0.1K2K2KK
Then the value of \(K\) is

  1. A \(0.15\)
  2. B \(0.20\)
  3. C \(0.12\)
  4. D \(0.16\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(0.15\)

Step-by-step Solution

Detailed explanation

\( \sum P(X) = 1 \) \( 0.1 + K + 2K + 2K + K = 1 \) \( 0.1 + 6K = 1 \) \( 6K = 1 - 0.1 \) \( 6K = 0.9 \) \( K = \frac{0.9}{6} \) \( K = 0.15 \)