CUET · MATHS · PYQ PAPER 2023
Let us consider an annuity whose periodic payment is ₹ R payable at the end of each payment period for ' \(n ^{\prime}\) periods, interest paid r% per period or \(i=\frac{r}{100}\), so the amount.
- A \(A=R\left[\frac{(1+i)^n-1}{i}\right]\)
- B \(A=R\left[\frac{(1-i)^n-1}{i}\right]\)
- C \(A=R\left[\frac{(1+i)^n}{i}-1\right]\)
- D \(A=R\left[i^{n-1}-1\right]\)
Answer & Solution
Correct Answer
(A) \(A=R\left[\frac{(1+i)^n-1}{i}\right]\)
Step-by-step Solution
Detailed explanation
The correct formula for the future amount A of an ordinary annuity is:\(A=R\left[\frac{(1+i)^n-1}{i}\right]\) This matches Option A, representing the sum of a geometric series for n periodic payments R at interest rate i. (A) \(A=R\left[\frac{(1+i)^n-1}{i}\right]\)
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