CUET · MATHS · PYQ PAPER 2025
Let the equations of lines be \(L_1: \vec{r}_1=\vec{a}_1+\lambda \vec{b}_1\) and \(L_2: \vec{r}_2=\vec{a}_2+\lambda \vec{b}_2\)
Then the shortest distance between \(L_1\) and \(L_2\) is
- A 20
- B 4
- C 0
- D \(2 \sqrt{3}\)
Answer & Solution
Correct Answer
(B) 4
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