CUET · MATHS · PYQ PAPER 2023
Let functions \(f:\{1,3,4\} \rightarrow\{1,2,5\}\) and \(g:\{1,2,5\} \rightarrow\{1,3\}\) be defined as \(f=\{(1,2),(3,5),(4,1)\}\) and \(g=\{(1,3),(2,3),(5,1)\}\) respectively. Then, which one of the following is correct statement for \(g \circ f\)?
- A \(g \circ f\)is one-one
- B \(g \circ f\) is onto
- C \(g \circ f\)is both one-one and onto
- D \(g \circ f\)is not defined
Answer & Solution
Correct Answer
(B) \(g \circ f\) is onto
Step-by-step Solution
Detailed explanation
\(g \circ f(1) = g(f(1)) = g(2) = 3\) \(g \circ f(3) = g(f(3)) = g(5) = 1\) \(g \circ f(4) = g(f(4)) = g(1) = 3\) \(g \circ f = \{(1,3), (3,1), (4,3)\}\) \(g \circ f(1) = g \circ f(4) = 3\), so not one-one. Range of \(g \circ f = \{1,3\}\) Codomain of \(g \circ f = \{1,3\}\)…
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