CUET · MATHS · PYQ PAPER 2023
Let \(f: R \rightarrow R\) be defined as \(f(x)=5 x^2\). Choose the correct answer :
- A \(f\) is one-one, onto
- B \(f\) is many to one, onto
- C \(f\) is one-one but not onto
- D \(f\) is neither one-one nor onto
Answer & Solution
Correct Answer
(D) \(f\) is neither one-one nor onto
Step-by-step Solution
Detailed explanation
\(f(1) = 5\) \(f(-1) = 5\) Since \(f(1) = f(-1)\) but \(1 \neq -1\), \(f\) is not one-one. For \(y = -5\), \(5x^2 = -5 \implies x^2 = -1\). No real \(x\) exists, so \(f\) is not onto. \(f\) is neither one-one nor onto.
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