CUET · MATHS · PYQ PAPER 2025
Let \(e^y(x+1)=1\). Then which of the following are TRUE
(A) \(\frac{d^2 y}{d x^2}=-\frac{1}{(x+1)^2}\)
(B) \(\frac{d^2 y}{d x^2}=\left(\frac{d y}{d x}\right)^2\)
(C) \(\left.\frac{d^2 y}{d x^2}\right|_{x=0}=-1\)
(D) \(\left.\frac{d^2 y}{d x^2}\right|_{x=0}=1\)
(E) \(\left.\frac{d^2 y}{d x^2}\right|_{x=1}=\frac{1}{4}\)
Choose the correct answer from the options given below :
- A (B),(D),(E) only
- B (A),(C) only
- C (B),(C) only
- D (A),(D),(E) only
Answer & Solution
Correct Answer
(A) (B),(D),(E) only
Step-by-step Solution
Detailed explanation
\(e^y(x+1)=1 \Rightarrow y = -\ln(x+1)\) \(\frac{dy}{dx} = -\frac{1}{x+1}\) \(\frac{d^2 y}{d x^2} = \frac{1}{(x+1)^2}\) (B) \(\left(\frac{dy}{dx}\right)^2 = \left(-\frac{1}{x+1}\right)^2 = \frac{1}{(x+1)^2}\) (D) \(\left.\frac{d^2 y}{d x^2}\right|_{x=0} = \frac{1}{(0+1)^2} = 1\)…
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