CUET · MATHS · PYQ PAPER 2025
Let \(\theta\) be the angle between two vectors \(\vec{a}\) and \(\vec{b}\). Then match List-I with List-II
| List-I | List-II |
| (A) \(\sin \theta\) | (I) \(\frac{\vec{a} \cdot \vec{b}}{|\vec{a}||\vec{b}|}\) |
| (B) \(\cos \theta\) | (II) \(|\vec{a} \times \vec{b}|\) |
| (C) Area of the parallelogram with adjacent sides represented by \(\vec{a}\) and \(\vec{b}\) | (III) \(\frac{\vec{a} \cdot \vec{b}}{|\vec{a}|}\) |
| (D) Projection of \(\vec{a}\) on \(\vec{b}\) | (IV) \(\frac{|\vec{a} \times \vec{b}|}{|\vec{a}||\vec{b}|}\) |
- A (A) - (IV), (B) - (I), (C) - (II), (D) - (III)
- B (A) - (I), (B) - (IV), (C) - (II), (D) - (III)
- C (A) - (IV), (B) - (I), (C) - (III), (D) - (II)
- D (A) - (I), (B) - (IV), (C) - (III), (D) - (II)
Answer & Solution
Correct Answer
(A) (A) - (IV), (B) - (I), (C) - (II), (D) - (III)
Step-by-step Solution
Detailed explanation
(A) \( \sin \theta = \frac{|\vec{a} \times \vec{b}|}{|\vec{a}||\vec{b}|} \) matches (IV). (B) \( \cos \theta = \frac{\vec{a} \cdot \vec{b}}{|\vec{a}||\vec{b}|} \) matches (I). (C) Area of the parallelogram \( = |\vec{a} \times \vec{b}| \) matches (II). (D) Projection of…
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