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CUET · MATHS · PYQ PAPER 2025

Let \(\theta\) be the angle between two vectors \(\vec{a}\) and \(\vec{b}\). Then match List-I with List-II
List-IList-II
(A) \(\sin \theta\)(I) \(\frac{\vec{a} \cdot \vec{b}}{|\vec{a}||\vec{b}|}\)
(B) \(\cos \theta\)(II) \(|\vec{a} \times \vec{b}|\)
(C) Area of the parallelogram with adjacent sides represented by \(\vec{a}\) and \(\vec{b}\)(III) \(\frac{\vec{a} \cdot \vec{b}}{|\vec{a}|}\)
(D) Projection of \(\vec{a}\) on \(\vec{b}\)(IV) \(\frac{|\vec{a} \times \vec{b}|}{|\vec{a}||\vec{b}|}\)
Choose the Correct answer from the options given below :

  1. A (A) - (IV), (B) - (I), (C) - (II), (D) - (III)
  2. B (A) - (I), (B) - (IV), (C) - (II), (D) - (III)
  3. C (A) - (IV), (B) - (I), (C) - (III), (D) - (II)
  4. D (A) - (I), (B) - (IV), (C) - (III), (D) - (II)
Verified Solution

Answer & Solution

Correct Answer

(A) (A) - (IV), (B) - (I), (C) - (II), (D) - (III)

Step-by-step Solution

Detailed explanation

(A) \( \sin \theta = \frac{|\vec{a} \times \vec{b}|}{|\vec{a}||\vec{b}|} \) matches (IV). (B) \( \cos \theta = \frac{\vec{a} \cdot \vec{b}}{|\vec{a}||\vec{b}|} \) matches (I). (C) Area of the parallelogram \( = |\vec{a} \times \vec{b}| \) matches (II). (D) Projection of…