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CUET · MATHS · PYQ PAPER 2025

Let \(\vec{a}=\hat{i}+\hat{j}+\hat{k}\) and \(\vec{b}=\hat{i}+2 \hat{j}+3 \hat{k}\), then a unit vector perpendicular to both vectors \((\vec{a}+\vec{b})\) and \((\vec{a}-\vec{b})\) is equal to

  1. A \(\frac{1}{\sqrt{6}}(-\hat{i}+2 \hat{j}-\hat{k})\)
  2. B \(\frac{1}{\sqrt{6}}(\hat{i}-2 \hat{j}-\hat{k})\)
  3. C \(\frac{1}{\sqrt{3}}(\hat{i}+\hat{j}+\hat{k})\)
  4. D \(\frac{1}{\sqrt{6}}(\hat{i}+2 \hat{j}+\hat{k})\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{1}{\sqrt{6}}(-\hat{i}+2 \hat{j}-\hat{k})\)

Step-by-step Solution

Detailed explanation

\( (\vec{a}+\vec{b}) = (\hat{i}+\hat{j}+\hat{k}) + (\hat{i}+2 \hat{j}+3 \hat{k}) = 2\hat{i}+3\hat{j}+4\hat{k} \) \( (\vec{a}-\vec{b}) = (\hat{i}+\hat{j}+\hat{k}) - (\hat{i}+2 \hat{j}+3 \hat{k}) = -\hat{j}-2\hat{k} \)…
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