CUET · MATHS · PYQ PAPER 2025
Let \(\vec{a}=\hat{i}+4 \hat{j}+2 \hat{k}, \vec{b}=3 \hat{i}-2 \hat{j}+7 \hat{k}\), and \(\vec{c}=2 \hat{i}+\hat{j}+4 \hat{k}\).
A vector \(\vec{d}\) which is perpendicular to both \(\vec{a}\) and \(\vec{b}\) and satisfies \(\vec{c} \cdot \vec{d}=14\) is :
- A \(64 \hat{i}+2 \hat{j}-28 \hat{k}\)
- B \(64 \hat{i}-2 \hat{j}-28 \hat{k}\)
- C \(64 \hat{i}+2 \hat{j}+28 \hat{k}\)
- D \(32 \hat{i}+\hat{j}+14 \hat{k}\)
Answer & Solution
Correct Answer
(B) \(64 \hat{i}-2 \hat{j}-28 \hat{k}\)
Step-by-step Solution
Detailed explanation
\( \vec{a} \times \vec{b} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \\ 1 & 4 & 2 \\ 3 & -2 & 7 \end{vmatrix} = (28 - (-4))\hat{i} - (7 - 6)\hat{j} + (-2 - 12)\hat{k} = 32\hat{i} - \hat{j} - 14\hat{k} \) \( \text{Let } \vec{d} = k(\vec{a} \times \vec{b}) \). Then…
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