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CUET · MATHS · PYQ PAPER 2025

Let \(\vec{a}, \vec{b}\) be two vectors such that \(|\vec{a}|=2,|\vec{b}|=3, \vec{a} \cdot \vec{b}=4\). Then \(|\vec{a}-\vec{b}|\) is equal to :

  1. A 0
  2. B \(\sqrt{5}\)
  3. C 5
  4. D 1
Verified Solution

Answer & Solution

Correct Answer

(B) \(\sqrt{5}\)

Step-by-step Solution

Detailed explanation

\(|\vec{a}-\vec{b}|^2 = |\vec{a}|^2 - 2(\vec{a} \cdot \vec{b}) + |\vec{b}|^2\) \(|\vec{a}-\vec{b}|^2 = (2)^2 - 2(4) + (3)^2\) \(|\vec{a}-\vec{b}|^2 = 4 - 8 + 9\) \(|\vec{a}-\vec{b}|^2 = 5\) \(|\vec{a}-\vec{b}| = \sqrt{5}\)
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