CUET · MATHS · PYQ PAPER 2025
Let \(A=\left[\begin{array}{ll}2 & 3 \\ 1 & 2\end{array}\right]\) and \(B=\left[\begin{array}{cc}4 & -6 \\ -2 & 4\end{array}\right]\), then
(A) \(\operatorname{det}\left(A^T\right)=1\)
(B) \(A B=I\), where \(I\) is the identity matrix of order 2
(C) \(A^{-1}=\left[\begin{array}{cc}2 & -3 \\ -1 & 2\end{array}\right]\)
(D) \(\operatorname{adj}(B)=\left[\begin{array}{ll}4 & 2 \\ 6 & 4\end{array}\right]\)
Choose the correct answer from the options given below :
- A (A) and (C) only
- B (B), (C) and (D) only
- C (A), (C) and (D) only
- D (A) and (B) only
Answer & Solution
Correct Answer
(A) (A) and (C) only
Step-by-step Solution
Detailed explanation
\(\operatorname{det}(A) = 2 \cdot 2 - 3 \cdot 1 = 1\) Statement (A): \(\operatorname{det}(A^T) = \operatorname{det}(A) = 1\). This statement is True. Statement (C):…
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