CUET · MATHS · PYQ PAPER 2025
Let \(\vec{a}\) and \(\vec{b}\) be unit vectors. If \(\sqrt{3} \vec{a}-\vec{b}\) is a unit vector, then the angle between \(\vec{a}\) and \(\vec{b}\) is
- A \(\frac{\pi}{6}\)
- B \(\frac{\pi}{4}\)
- C \(\frac{\pi}{3}\)
- D \(\frac{\pi}{2}\)
Answer & Solution
Correct Answer
(A) \(\frac{\pi}{6}\)
Step-by-step Solution
Detailed explanation
\(|\sqrt{3} \vec{a}-\vec{b}|^2 = 1^2\) \(3|\vec{a}|^2 - 2\sqrt{3}(\vec{a} \cdot \vec{b}) + |\vec{b}|^2 = 1\) \(3(1)^2 - 2\sqrt{3}|\vec{a}||\vec{b}|\cos\theta + (1)^2 = 1\) \(3 - 2\sqrt{3}(1)(1)\cos\theta + 1 = 1\) \(4 - 2\sqrt{3}\cos\theta = 1\) \(2\sqrt{3}\cos\theta = 3\)…
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